Well, again, I suggest taking a look at a Springfield '03 ladder sight. It can't quite be ignored. A foot at 1000 yards is roughly equal to 1 mph wind drift. That gives you a sense of the scale. It's not a lot to most shooters, but it is enough to make a sniper miss a man-size target at that range if he fails to dial it in.
Mike,
you are describing a projectile whose center of pressure is behind its center of gravity. Such shapes are inherently stable. An arrow with feathers is an example. More drag to the rear of the center of gravity points the projectile into the wind because it pivots around its center of gravity.
Most modern pointy shape bullets, however, are the other way around with center of pressure ahead of center of gravity. So, imagine shooting an arrow backward and having to make it spin fast enough to keep pointing straight ahead despite air pressure trying to turn it by it force on the feathers.
If a bullet is spinning fast enough to be stable and has gone to sleep and is flying steady, the upward tipping force (the overturning moment) puts vertical momentum into the bullet by trying to flip it. What stops it fröm flipping the bullet into a tumble is that overturning momentum is translated into the downward direction half a turn later, neutralizing it and that happens faster than the tumble can initiate. This is intrinsic to what defines spinning fast enough to be stable.
The injection of upward momentum and its neutralization by translation is a continuous process for the flying bullet. The faster the bullet spins the more gyroscopic force it has trying to hold its nose up, but that increases the the overturning momentum that gets translated around to the bottom to pull the tip back down.
So, the yaw upward above tangent to the trajectory path is a position representing equilibrium between those two influences: the gyroscopic tendency to fix orientation, and the constant downward translation of overturning momentum due to spinning. The faster the spin, the more the bullet tries to hold its orientation, so the more it is chin up and the more overturning force is applied to create more vertical momentum that is translated down to oppose the upward tipping. The exact value of the neutralizing momentum is always lagging by half a turn, so it is never 100%. Therefore the equilibrium position of the nose is higher for higher gyroscopic stability (faster spin relative to forward velocity), which results in more effect fröm both influences.
Keep in mind we are talking about numbers in thousandths of an inch above the tangent to the trajectory path. IIRC, Harold Vaughn had examples like 0.003" to 0.009" nose up off the trajectory for a range of stability factors. As former head ballistician for Sandia National Laboratories, his book is a worthwhile read on these and other accuracy topics.
Mike,
you are describing a projectile whose center of pressure is behind its center of gravity. Such shapes are inherently stable. An arrow with feathers is an example. More drag to the rear of the center of gravity points the projectile into the wind because it pivots around its center of gravity.
Most modern pointy shape bullets, however, are the other way around with center of pressure ahead of center of gravity. So, imagine shooting an arrow backward and having to make it spin fast enough to keep pointing straight ahead despite air pressure trying to turn it by it force on the feathers.
If a bullet is spinning fast enough to be stable and has gone to sleep and is flying steady, the upward tipping force (the overturning moment) puts vertical momentum into the bullet by trying to flip it. What stops it fröm flipping the bullet into a tumble is that overturning momentum is translated into the downward direction half a turn later, neutralizing it and that happens faster than the tumble can initiate. This is intrinsic to what defines spinning fast enough to be stable.
The injection of upward momentum and its neutralization by translation is a continuous process for the flying bullet. The faster the bullet spins the more gyroscopic force it has trying to hold its nose up, but that increases the the overturning momentum that gets translated around to the bottom to pull the tip back down.
So, the yaw upward above tangent to the trajectory path is a position representing equilibrium between those two influences: the gyroscopic tendency to fix orientation, and the constant downward translation of overturning momentum due to spinning. The faster the spin, the more the bullet tries to hold its orientation, so the more it is chin up and the more overturning force is applied to create more vertical momentum that is translated down to oppose the upward tipping. The exact value of the neutralizing momentum is always lagging by half a turn, so it is never 100%. Therefore the equilibrium position of the nose is higher for higher gyroscopic stability (faster spin relative to forward velocity), which results in more effect fröm both influences.
Keep in mind we are talking about numbers in thousandths of an inch above the tangent to the trajectory path. IIRC, Harold Vaughn had examples like 0.003" to 0.009" nose up off the trajectory for a range of stability factors. As former head ballistician for Sandia National Laboratories, his book is a worthwhile read on these and other accuracy topics.